SUNY Geneseo Department of Mathematics

Volume by Slices

Wednesday, May 8

Math 221 03
Spring 2019
Prof. Doug Baldwin

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Misc

Extended MLC Hours

9:00 AM to 3:30 PM weekdays through Wednesday of finals (added 1 to 1 1/2 hours front and back).

Evening hours unchanged (as far as I can see).

Reading Survey

For the math department assessment committee.

Visit https://forms.gle/rctWLa7Rxt19RHfj8 and fill out the form.

OR get a paper copy from me, fill it out, and return it to me.

Extra Credit

“Due” by the final exam.

SI

Review today, 4:00 - 7:00, Bailey 209.

Review Session

Tomorrow.

1:00 - 2:00

In our regular classroom (Sturges 221).

Bring things you want to talk about.

Final Exam

Thursday, May 16, 12:00 Noon.

In our regular room.

Comprehensive, but emphasizing material since the 2nd hour exam (e.g., Mean Value Theorem, limits at infinity, Riemann sums, definite integrals, substitution, applications of integration; roughly problem sets 7 through 9).

Rules and format otherwise similar to hour exams, especially open-references rule.

Designed for about 2 hours, you’ll have 3 hours 20 minutes

Practice questions are now available in Canvas.

I’ll bring donuts and cider.

SOFIs

SOFIs are under way.

11 responses (35%) so far. Thank you!

But please keep filling them out. I do read them and apply the feedback where possible to future classes (like the mid-semester feedback).

Questions?

Volume via Slices

Section 6.2.

Introductory Example

Last class we discovered that volumes of irregular shapes can (sometimes) be calculated as sums of volumes of thin slices, which leads to volume as a Riemann sum and thus as an integral:

Volume of a tapered prism is integral over its length of its cross-section

So what is the volume of that prism?

Integrate 3 x squared from 0 to 1 to get 1

Side question: if the bounds of an integral reverse (i.e., upper bound has smaller numeric value than lower), do you have to do anything special to evaluate it? No, the “subtract antiderivative at lower bound from that at upper bound” rule takes care of it for you. For example...

Integral from 1 to 0 of 3 times x squared is negative 1

A Volume of Revolution

Suppose you take the region between the line y = x/2 and the x axis, from x = 0 to x = 2, and spin it around the x axis to form a cone. What is the volume of that cone?

Diagonal line rotated around x axis creates a cone

The area of a circle seems relevant, but how? Because thin slices of the cone have circular faces, and so their volumes are the areas of those circles times their thicknesses:

Cone from revolving line with cross-section highlighted, section volume is pi times t squared times delta x

Now the approximate volume of the cone is a Riemann sum of volumes of thin slices, so the exact volume is an integral, which can be evaluated like any other definite integral:

Integral from 0 to 1 of pi times quantity x over 2 squared is pi over 12

Here’s the complete volume calculation, as it looked when we finished it in class:

Rotating a line to produce a cone and finding its volume

Rotation Around Other Axes

What if you rotate the line y = 3x, between x = 0 and x = 1, around the y axis to make a cone? What’s the volume of that cone?

The ideas are the same as above, except now it’s easiest to take slices perpendicular to the y axis, not the x. So re-express x in terms of y (since the x value will be the radius of the cone at any particular y), and figure out the range of y values the cone covers:

Line rotated around y axis makes vertical cone; integrate slice volumes with respect to y

Now integrate with respect to y:

Integral from 0 to 3 of pi times quantity y over 3 squared is pi

Here’s the complete picture and calculation, as they appeared when we finished:

Rotate line around y axis to get vertical cone, integrate in terms of y

Key Points

To find a volume by slicing:

You can do this around any axis.

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