SUNY Geneseo Department of Mathematics

Integration by Substitution, Part 1

Monday, April 29

Math 221 03
Spring 2019
Prof. Doug Baldwin

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Misc

“Town Hall” re Bias Incidents

Tuesday (tomorrow) 5:00 - 8:00 PM, Macvittie Ballroom.

Hosted by student group Activists Fighting Racial Oppression (AFRO).

RSVP by 10:00 AM Tuesday at https://docs.google.com/forms/d/e/1FAIpQLScATpC6NTbGh3LDd_gfYHzGTvZOGrMX3pN1kO1oh-h1Upu5qA/viewform?usp=sf_link

Final Exam

Thursday, May 16, 12:00 Noon.

Comprehensive, but emphasizing material since 2nd hour exam (e.g., Mean Value Theorem, limits at infinity, Riemann sums, definite integrals, substitution, applications of integration; roughly problem sets 7 through 9).

Rules and format otherwise similar to hour exams, especially open-references rule.

Designed for about 2 hours, you’ll have 3 hours 20 minutes

I’ll put together some practice questions.

I’ll bring donuts and cider.

Would you like a roughly 1 hour review session on study day? Yes!

SOFIs

SOFIs have started!

Please fill them out. I do read them and apply the feedback where possible to future classes (like the mid-semester feedback).

Questions?

Breaking sums into parts? One way to do this is to break a sum that contains a sum or difference of two terms into a sum or difference of the sums of each term. For example...

Sum from 1 to n of 3i plus 7 is sum of 3i plus sum of 7

But there’s not an analogous way to break up a product inside a sum. In such cases, you have to hope you can algebraically rewrite the product into something you can work with. For example...

Finding a closed form for the sum from 1 to n of 3i times the quantity 7 plus i squared

Definite Integrals with Mathematica

Use the Integrate function with a range of values for the variable.

This notebook demonstrates both a definite integral and an antiderivative. (And how to use Mathematica to quickly look something up, in this case the closed form for the sum from 1 to n of i3.)

Integration by Substitution

Section 5.5

Basic Idea

What is the antiderivative of sin2x cosx?

What does it have to do with the reading?

U-substitution: similar to the chain rule for taking derivatives, u-substitution lets you find antiderivatives in certain cases where an outer function is applied to an inner one. (In fact u-substitution is exactly the inverse of the chain rule, i.e., it finds antiderivatives that would then need the chain rule in order to be differentiated.)

Antiderivative with outer function, inner function, and inner function's derivative

But the limit to when you can use substitution is that in addition to having an inner function g(x), you also have to have its derivative, g′(x). This is because in substitution you want to replace dx with du as well as replacing expressions involving x with ones involving u:

Derivative of u with respect to x equals g prime implies differential of u is g prime times differential of x

The whole u-substitution idea as it appeared in class is...

Antiderivative of outer and inner function with derivation of d u

Try applying this to the sin2x cosx example. Start by identifying u and its derivative:

In sine squared times cosine, u can be sine and d u cosine times d x

Then express the problem in terms of u and apply antiderivative rules:

Antiderivative of u squared is one third u cubed

Finally, replace u with its definition in terms of x:

One third u cubed becomes one third sine cubed

And here’s the whole substitution example as it looked at the end of our discussion in class:

Integrate sine squared times cosine via u substitution

Key Points

Substitution is a technique for finding antiderivatives when there is an outer function, and an inner function with its derivative.

Next

More examples of substitution.

Read section 5.5 if you haven’t already.

Next Lecture