SUNY Geneseo Department of Mathematics
Monday, April 22
Math 221 03
Spring 2019
Prof. Doug Baldwin
Colloquium on Thursday (April 25), 2:30 - 3:30, Welles 138
Prof. Sedar Ngoma
“An Introduction to Finite Difference Methods”
Extra credit for reflection/connection paragraphs.
Section 5.2.
We saw one example Friday: the area between the graph of y = x and the x axis, from x = 1 to x = 3, is a definite integral.
Find the integral from 0 to 2 of x3 as a limit of a Riemann sum.
The basic idea is that the integral represents (among other things) the area under the graph of x3 between x = 0 and x = 2. But as we saw last week, that area can also be approximated as a sum of many rectangles:
In fact, the area is calculated ever more exactly as the number of rectangles increases, and in the limit as the number of rectangles becomes infinite, the sum gives the exact area. So we have two equal ways of looking at the same thing:
Realize that Δx, the width of each rectangle, is just the width of the whole interval from 0 to 2 divided by n, i.e., 2/n. Then pick xi, the x value in the ith rectangle, to be the right edge of that rectangle, so that xi is just i times Δx. This lets us fill in lots of parts of the sum for this particular problem:
A good next step is to do the multiplications inside the sum:
Then factor all the constants out of the sum:
This leaves us with a sum of i3. There’s a good chance that such a simple sum has a known closed form (at least known to textbook authors and Google), so see if we can look it up. In fact, there’s a rule for it in our book. Use that rule to eliminate the sum altogether:
Now simplify...
And finally we can take the limit, since in the simplified form all the terms with n go to 0 as n goes to infinity:
Here’s the complete record of how all this looked by the time we finished it in class:
(A more general version of the process we identified last Friday for evaluating the area under a graph.)
To evaluate the definite integral of f(x) from x = a to x = b as a Riemann sum...
Some properties of integrals you can use to (sometimes) avoid having to evaluate Riemann sums.
Read the “Properties of the Definite Integral” subsection of section 5.2 if you haven’t already.
(Then eventually, how to evaluate definite integrals without Riemann sums at all.)