SUNY Geneseo Department of Mathematics

Density and Mass

Thursday, December 7

Math 221 05
Fall 2017
Prof. Doug Baldwin

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Previous Lecture

Misc

Review Session

Tuesday, Dec. 12, 9:30 - 10:30 AM, Fraser 213 (our Thursday room).

You bring topics/questions you want to review.

Final

Thursday, December 14, 8:00 AM, in our MWF Sturges classroom (Sturges 223).

The exam will cover the whole semester, but emphasizing material since the second hour exam (e.g., the Fundamental Theorem; substitution; area, volume, and similar applications of definite integrals; etc.)

Roughly 2 to 2 1/2 times as long as the hour exams in terms of number of questions and design time. But note that you have roughly 4 times as long in terms of actual time, so there should be less time pressure.

The rules and format will otherwise be the same as on the hour exams, particularly the open-references and calculator rules.

I’ll bring donuts and cider.

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Questions?

Mass and Density

The first subsection of section 6.5

Warm-Up

Find the mass of a section of thin wire between x = 1 and x = 3, if the linear density of the wire at position x is given by ρ(x) = x2 / 3 - 4x g/cm. (Notice that this is a completely arbitrary function, and accidentally gives negative densities over the interval [1,3]. This means the mass will be negative — we’ve apparently invented antigravity wire!)

Line from x = 1 to x = 3 with density 1/3 x^2 - 4x

The reading gives a formula for mass from linear density:

Mass equals integral from a to b of rho(x)

This formula follows from the idea that mass equals density times volume. When the density varies, you can’t just multiply the two together, but you can break the volume into smaller and smaller sections, each of which has a more and more nearly constant density over it. Adding all the masses estimated for these sections gives a total mass. But this is a Riemann sum, and so in the limit as the number of sections goes to infinity it gives you this integral.

Now plug the density function into this integral, using the endpoints of the wire as the bounds, to get

M equals integral from 1 to 3 of 1/3 x^2 - 4x which equals -13 1/9

Realistic Rod

Textbook examples using functions chosen more for ease of integration than anything else don’t necessarily convince you that this technique is useful. So here’s a more physically realistic example (though still not one you couldn’t do by other means): Consider a 1 meter metal rod, 1 cm in radius, which is pure lead (volume density about 11 g/cm3) at one end and pure iron (volume density about 8 g/cm3) at the other, with the lead/iron blend changing linearly along the length of the rod. What’s the mass of the rod?

Cylinder of radius 1 cm and length 100 cm, density 11 g/cm^3 at left end and 8 g/cm^3 at right

This problem doesn’t particularly fit the template given in the book. First, it has volume densities, not linear ones, and second there’s no function giving density in terms of x (indeed, there’s no x axis at all). To deal with the first problem, note that linear density is mass per unit of length, i.e., the weight of 1 cm of the rod. Since sections of the rod are cylinders, find this mass by multiplying the cross-sectional area of the rod by 1 to get volume, and then multiplying that volume by the volume density to get linear density:

Cross section area = pi so linear densities are 11 pi g/cm and 8 pi g/cm

Now you can come up with a linear density function by letting the lead end of the rod be at x = 0 and the iron end at x = 100. Then multiply the lead density by something that varies linearly from 1 when x = 0 to 0 when x = 100, and the iron density by something that varies linearly from 0 when x = 0 to 1 when x = 100. (1 - x/100) and x/100 serve well as these “somethings”:

rho(x) = (1-x/100) 11 pi + (x/100) 8 pi which equals pi/100 (1100 - 3x)

Now there’s a linear density function, and some bounds to integrate it over. Do so:

M equals integral from 0 to 100 of pi/100 (1100 - 3x) which equals 950 pi grams

Take-Aways

Find masses from linear densities by identifying the density function and the bounds within which it applies, then integrating it over those bounds.

Next

Look at work as an integral.

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