SUNY Geneseo Department of Mathematics
Wednesday, September 6
Math 221 05
Fall 2017
Prof. Doug Baldwin
Opens today.
Hours are generally
On the 3rd floor of South Hall.
This is a somewhat odd looking application of the law that says any limit of a constant is that constant.
Problem. Use limit laws to confirm Friday’s guess that limx→13x2 = 3.
Reading ideas: The constant multiple and power laws will be helpful here.
Having done this once, you won’t normally have to write out uses of the limit laws in this much detail.
Take-Away. The limit laws let you break down complicated limit expressions into combinations of simpler ones, until (hopefully) you reach simple limits limx→ac or limx→ax.
Problem. Find limx→1(x2 + 2x - 3) / (2x-2).
Reading ideas: Right now the quotient law for limits doesn’t apply because limx→1(2x-2) = 0, so use algebra to simplify the expression until the limit laws do apply.
Notice that technically the function we finally took a limit of, (x+3)/2, is not the same function as the one we started with, because (x+3)/2 has one more point in its domain than the original function did.
Problem. Find limx→25(√x - 5) / (x - 25).
Reading ideas. The trick of multiplying by a conjugate to get rid of a square root will help here.
Problem. Find limx→0 x / (1+1/x).
Take-Aways. Algebraically rewriting limit expressions that can’t be evaluated using the limit laws can sometimes put them into forms that can be evaluated. Factoring to cancel out a problem denominator, and multiplying by a conjugate to remove a square root, are two useful tactics, but not the only ones.
One-sided limits.
Read the “One-Sided Limits” subsection in section 2.2.