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Spring Motion

Created by: Salvador Galarza & Jack Truckenmiller

Under Damped

Canvas not Supported

Solution:

$$x(t) = -4e^{-0.09t}\cos(1.11t) - 0.31e^{-0.09t}\sin(1.11t)$$
\(x’’ +\) \(x’ +\) \(x =\)

Initial Conditions

\(t_0 =\)

\(x_0 =\)

\(v_0 =\)

\(x\) Axis

\(x\)-min =

\(x\)-max =

\(x\)-step =

\(t\) Axis

\(t\)-min =

\(t\)-max =

\(t\)-step =