These are the mistakes that students have already found.
Please check here before sending me one.
I found an error in section 0.5 in the grey box labeled
Substitution with Indefinite Integrals. The problem states Let u
=g(x),, where g'(x) is continuous over an interval... There are
two commas after g(x) at the beginning of the sentence where there
should only be one.
I found a second error, this time a mathematical error in the
textbook. The problem is located in section 0.6 in example
0.6.4:Finding a Price-Demand Equation. In this problem,
in the very last step, 100 is supposed to be plugged into
p(x) to solve for the price. When the author solved the problem
the -0.01(100) was brought down from the exponent. This changed
the problem to become p(100) = 1.5e - 0.01(100) + 1.44 = 1.99. If
you were to plug the exact problem they wrote for p(100) the value
is $4.517. However, if you properly plugged 100 in for x in the
exponent shown in p(x) the equation would then be p(100) =
1.5e^(-0.01(100)) +1.44 = 1.99. Which when solved does
indeed give you $1.99.
In question 60 of the exercises for0.6 the question asks
for you to compute the integral of an equation from N to N+10, but
in the answer this integral is shown going from N to N+1.
1.1 #21 It says one of the equations is x=y but on the graph it
says x=2y.
1.1 Question 39 involves something we don't know how to do
yet (integrating (1-x^2)^1/2).
In section 1.1 of the textbook, the answer to question #27 is
wrong. After doing the calculations, I got an answer of e-2
units squared
and the textbook says the answer is e^-2 units squared. I think
the textbook accidentally put the minus two as an exponent
when that is not necessary for this problem.
Question 29 in 1.1 asks for the area between X=y^3+2y^2+1
and X=-y^2+1 but the graph it shows in the solution is the area
between
X=y^3+2y^2 and X=-y^2+1 The graph in the written directions
does not intersect in a way for the area between the curves to be
found. The plus one in X=y^3+2y^2+1 is unwanted.