SUNY Geneseo Department of Mathematics
Friday, February 8
Math 239 01
Spring 2019
Prof. Doug Baldwin
Parts of section 2.3 of our textbook.
Use roster notation to write the set of majors represented in our class: { Education, Math, Physics }. This is the simplest form, a short list of elements inside braces. Notice that the elements don’t have to be numbers or anything particularly mathematical.
Use roster notation to write the following:
Are any of the above sets subsets of others? Which ones? List the subset relationships using the ⊆ symbol.
B ⊆ D, A ⊆ ℕ, ℕ⊆C, verified by checking that every element the first set in each example is a member of the second.
E is a subset of all of them, i.e., the empty set is a subset of everything.
Every set is a subset of itself, too.
For which of the above sets, X, is it true that 0 ∈ X? D, for example.
Are any of the above sets equal to each other? No, none contain exactly the same elements.
Prove the following theorem: The set of real-valued solutions to the equation x2 - 4 = 0 is a subset of the set of real-valued solutions to the equation x3 + x2 - 4x - 4 = 0.
The key goal is to show that every solution to x2 - 4 = 0 is also a solution to x3 + x2 - 4x - 4 = 0. There are several ways you could do this, but the most elegant we heard uses factoring. Formally, a proof might go like this (notice that I used the definition of subset to restate the theorem):
Theorem: If y is a real-valued solution to x2 - 4 = 0, then y is also a solution to x3 + x2 - 4x - 4 = 0.
Proof. We assume that y is a solution to x2 - 4 = 0, and will show that y is also a solution to x3 + x2 - 4x - 4 = 0. Since y is a solution to x2 - 4 = 0, we have that y2 - 4 = 0. Now observe that x3 + x2 - 4x - 4 factors into
x3 + x2 - 4x - 4 = (x2 - 4)(x+1).
Plugging y into this equation yields
y3 + y2 - 4y - 4 = (y2 - 4)(y+1)
= 0
where the last equality holds because y2 - 4 = 0. We have thus shown that if y is a real-valued solution to x2 - 4 = 0, then y is also a solution to x3 + x2 - 4x - 4 = 0. QED.
So now you’ve seen how to build proofs that one set is a subset of another around the definition of “subset”: to show the X is a subset of Y you just have to show that every member of X is also a member of Y, which in turn is just the conditional “if x is a member of X, then x is a member of Y.”
Roster notation is limited in what it can describe.
Predicates and set builder notation.
Read the rest of section 2.3 of the textbook (preview activity 2, “Variables and Open Sentences,” “Set Builder Notation,” “When the Truth Set is the Universal Set”).