SUNY Geneseo Department of Mathematics
Tuesday, March 7
Math 223
Spring 2023
Prof. Doug Baldwin
(No.)
The Math Learning Center closes for break this Thursday (March 9) at 6:00 PM.
It reopens after break on Monday, March 20 at 9:30 AM.
Based on section 3.2 in the textbook.
The definition of a multivariable limit. The definition captures the idea that in order for the limit of a multivariable function f(x,y,z,...) to be L as the inputs approach some point P, it must be the case that you can get f to come arbitrarily close (i.e., within tolerance ε) to L by bringing the inputs close enough (within distance δ) of P.
Multivariable limit laws are analogous to the single-variable ones.
Recognizing when a limit doesn’t exist is more complicated than in the single-variable case (we’ll talk more about this tomorrow).
The definition of continuity is the same as for single-variable functions, namely f is continuous at point P if f(P) is defined, the limit as the inputs approach P is defined, and the function’s value and the limit are equal.
New vocabulary of interior points, boundary points, open vs closed regions, connected regions, etc. will reappear throughout our later study of multivariable functions.
Find lim(x,y)→(1,2) (x2 + y2) / (x - 2y)
You can just plug in 1 for x and 2 for y and evaluate to find this limit. But remember that “just plug in” is really shorthand for using limit laws over and over (in this case, the quotient law, then addition, power law, etc.)
How about lim(x,y,z)→(-2,2,1) (x2 - y2) / z(x + y)
If you plug in x = -2, y = 2, and z = 1 you get an indeterminate form 0/0. Unfortunately, L’Hôpital’s Rule doesn’t apply to multivariable functions, so you have to deal with indeterminate forms by trying to algebraically simplify the expression whose limit you’re taking. In this case, we did that by factoring the numerator and then canceling:
Is f(x,y,z) = x(y - z) / (xy + xz) continuous at (0, 1, 2)?
Checking the requirements for continuity, we find that the limit exists, but the function is undefined at (0, 1, 2), so the function is not continuous there:
How about at (2, 1, 0)?
Here the function and limit both exist and are equal, so the function is continuous:
Limits that don’t exist, and vocabulary related to regions, their interiors and boundaries, etc.
No new reading.