Intuitively, connected means you can draw a possibly curved line between any 2
points in the set without leaving the set
Simply connected means any circle in the set can be pulled tight into a point
without leaving the set
Path independence ?
You saw an example when we integrated work over 2 flights of stairs that reached
the same height—the integrals were the same, independent of the path of the
stairs
Integral of F same over all paths
Equivalent to field being conservative
F is field = gradient of f ?
Main new thing here is name “potential function,” a label that’s
useful for talking about integrals of conservative fields
f is potential function for F
Fundamental theorem of line integrals
Conservative fields are gradient fields ?
This basically just states a useful connection between 2 kinds of vector fields
Closed loop integral = 0 iff field conservative ?
That the integral is 0 follows from the fundamental theorem
But other direction also interesting, i.e., if you find that integrals around
closed loops are always 0 then you know your field is conservative
Component test for conservative fields ?
Unintuitive now, but we may be able to see where this comes from in a week or
so
Exact differential forms ?
M(x,y,z) dx + N(x,y,z) dy + P(x,y,z) dz
Exactness captures the differential form of those line integrals that happen to
be of vector fields
Examples
Let f(x,y,z) = x(y-sin(z2)) / (z2 + exy), let
F = grad f, and let C be the curve x = sint cost, y = t2(π/2-t),
z = π, 0 ≤ t ≤ π/2
Find the integral of F around C
0, by closed loop theorem and because F is conservative—it’s
a gradient field
Find the integral of F from ( 0, 0, 0 ) to ( 1, 0, √(π/2) )
By fundamental theorem, integral = f(1, 0, √(π/2) ) - f( 0, 0, 0 )