SUNY Geneseo Department of Mathematics
Tuesday, October 18
Math 223 01
Fall 2022
Prof. Doug Baldwin
(No.)
Based on “Directional Derivatives” in section 3.6 of the textbook.
The directional derivative equation basically scales rates of change in the x and y (and more, if there are more than 2 variables) directions by the components of a unit vector that defines the direction in which you want a rate of change:
Suppose you’re standing at point (0, 0, 0) on the surface of the “egg-carton” function, z = sin x cos y.
What’s the instantaneous rate of change in z if you move in the x direction? What about if you move in the y direction? What if you move in a direction angled 45˚ to the x axis?
The rates of change as you move in the x and y directions are the partial derivatives with respect to x and y, respectively. The rate of change at a 45 degree angle is the directional derivative with Θ = 45˚.
What is the derivative of f(x,y) = 4 - x2 - y2 in direction 〈 1/2, -√3/2 〉?
Use the version of the directional derivative equation in terms of the components of the direction vector. But beware that to do this, that vector needs to be a unit vector — which it is in this case:
What about in direction 〈 -4, 2 〉?
Follow the same idea as above, except that this time the direction vector isn’t unit-length. So scale it to unit length first, then plug its components into the equation for a directional derivative.
The basic formula for a directional derivative of f(x,y) in the direction of a unit vector 〈 ux, uy 〉 is Duf(x,y) = fx(x,y) ux + fy(x,y) uy.
Can you think of this expression as a dot product? If so, what are the vectors involved in it?
You can, and the vectors are the direction vector u, and a vector of partial derivatives:
That vector of partial derivatives comes up in a lot of contexts, so much so that it has a name: the “gradient.”
It’s the next thing we’ll talk about.
To get ready, please read “Gradient” and “Gradients and Level Curves” in section 3.6 of the textbook.