SUNY Geneseo Department of Mathematics

Derivatives and the Shapes of Graphs, Part 2

Friday, November 6

Math 221 02
Fall 2020
Prof. Doug Baldwin

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Sunday 6:00 - 7:30. Review of the past week and a chance to go over problem set questions. Watch for an announcement Sunday afternoon with a Zoom link.

Derivatives and Graphs

Particularly based on “Concavity and Points of Inflection” and “The Second Derivative Test” in section 4.5 of the book and the ongoing discussion of derivatives and the shapes of graphs.

The Second Derivative Test

What is it and how does it work?

It’s a way to tell whether a critical point corresponds to a minimum or maximum (or neither), based on how the second derivative indicates the “concavity” of a function.

“Concavity” is whether a function is bending in a way that makes its graph head more upward (concave up, and notice that even a graph that’s decreasing can be concave up, if the rate of decrease is slowing down) or bending to head more downward (concave down).

If a graph is concave up, then its derivative is increasing, and so its second derivative is positive. Similarly, if a graph is concave down then its second derivative is negative:

As a special case, points where concavity changes from up to down or vice versa have second derivatives of 0 (assuming the second derivative is continuous). Such points are called “inflection points.”

Graph with downward loop opening up (concave up) and upward loop opening down (concave down)

Notice how an extreme value that occurs where a graph is concave down has to be a local maximum, and one that occurs where a graph is concave up has to be a local minimum. Thus the second derivative test:

How would this test work with yesterday’s example of an extreme point of 1 - xe-x at 1?

Start by finding the second derivative:

Second derivative is 2 e to the minus x minus x e to the minus x

Then plug x = 1 into the second derivative and see what the sign is:

Second derivative at 1 is e to the minus 1 which is positive

Since the second derivative is positive at x = 1, the critical point corresponds to a minimum.

You could also reach the same conclusion, for essentially the same reason, if you were able realize by inspecting it that the first derivative is positive on both sides of x = 1.

What about the critical point of x5 at 0 that turns out not to be an extreme point?

Second derivative of x to the fifth is 20 x to the third which is 0 at 0

This time the second derivative is 0 at x = 0, so the second derivative test doesn’t tell you whether 05 is a minimum or maximum.

The Graphs Game

A game in which one player (or team) tries to communicate a simple line drawing to another player or team by describing only the derivatives of the lines involved. See yesterday’s class and the discussion for further description of the game and rules, but the key rules are...

We came up with 2 examples, in both cases having teams of students give me descriptions of drawings and seeing if I could reproduce them.

The first was meant to be the letter w, and the sketch I came up with looked like...

Function and derivative information with graph looking like lowercase 'w'

The second was a “squiggle,” and I came up with...

Function and derivative information with sinusoidal graph

Next

The “end behavior” of graphs, i.e., how they behave as x approaches ∞ or -∞.

Please read “Limits at Infinity” in section 4.6 of the textbook.

Also contribute to this discussion of limits at infinity.

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